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Algebra: Identities, Surds, Indices and Linear Equations for SSC & Railway Exams

Core identities, the x + 1/x family, the a + b + c = 0 rule, linear equations and graphs, laws of indices and surds, with fresh worked examples.

60-second revision

  • x + 1/x = k gives x² + 1/x² = k² − 2 and x³ + 1/x³ = k³ − 3k.
  • x − 1/x = k gives x² + 1/x² = k² + 2 and x³ − 1/x³ = k³ + 3k.
  • If a + b + c = 0, then a³ + b³ + c³ = 3abc.
  • a³ + b³ = (a + b)³ − 3ab(a + b).
  • ax + by = c cuts the axes at (c/a, 0) and (0, c/b).
  • To solve index equations, write both sides with the same base and equate powers.
  • Rationalise by multiplying with the conjugate: (sqrt(a) + sqrt(b))(sqrt(a) − sqrt(b)) = a − b.

Identities to know cold

IdentityExpanded form
(a + b)²a² + 2ab + b²
(a − b)²a² − 2ab + b²
a² − b²(a + b)(a − b)
(a + b)³a³ + b³ + 3ab(a + b)
(a − b)³a³ − b³ − 3ab(a − b)
a³ + b³(a + b)(a² − ab + b²)
a³ − b³(a − b)(a² + ab + b²)
(a + b + c)²a² + b² + c² + 2(ab + bc + ca)
a³ + b³ + c³ − 3abc(a + b + c)(a² + b² + c² − ab − bc − ca)

Worked example: if a − b = 4 and ab = 5, then a² + b² = (a − b)² + 2ab = 16 + 10 = 26, and a³ − b³ = (a − b)³ + 3ab(a − b) = 64 + 60 = 124.

The x + 1/x family

  • x + 1/x = k: x² + 1/x² = k² − 2, x³ + 1/x³ = k³ − 3k.
  • x − 1/x = k: x² + 1/x² = k² + 2, x³ − 1/x³ = k³ + 3k.
  • x^4 + 1/x^4 = (x² + 1/x²)² − 2.

Worked example: x + 1/x = 4. Then x² + 1/x² = 14, x³ + 1/x³ = 64 − 12 = 52, and x^4 + 1/x^4 = 196 − 2 = 194.

When a + b + c = 0

Then a³ + b³ + c³ = 3abc. Example: 7, −3, −4 add to 0, so 343 − 27 − 64 = 252 = 3 × 7 × (−3) × (−4). The same fact gives (x − y)³ + (y − z)³ + (z − x)³ = 3(x − y)(y − z)(z − x).

Linear equations

One variable: expand, collect x terms on one side, divide. Two variables: substitute or eliminate.

Worked example: 4x − 3y = 1 and 2x + y = 13. From the second, y = 13 − 2x. Substituting, 4x − 39 + 6x = 1, so x = 4 and y = 5.

For a1x + b1y = c1 and a2x + b2y = c2SolutionsLines are
a1/a2 not equal to b1/b2Exactly oneIntersecting
a1/a2 = b1/b2, but not equal to c1/c2NoneParallel
a1/a2 = b1/b2 = c1/c2Infinitely manyCoincident

Linear graphs

  • ax + by = c meets the x-axis at (c/a, 0) and the y-axis at (0, c/b).
  • Area of the triangle it makes with the axes = 1/2 × |c/a| × |c/b|.
  • In y = mx + c, m is the slope and c is the y-intercept; parallel lines share the same slope.
  • x = k is a vertical line, y = k a horizontal line; the x-axis is y = 0.

Worked example: 5x + 2y = 20 meets the axes at (4, 0) and (0, 10); the triangle has area 1/2 × 4 × 10 = 20 square units.

Indices

LawExample
a^m × a^n = a^(m + n)2^3 × 2^4 = 2^7
a^m ÷ a^n = a^(m − n)5^6 ÷ 5^4 = 25
(a^m)^n = a^(mn)(3^2)^3 = 3^6
a^0 = 1, a^(−n) = 1/a^n4^(−2) = 1/16
a^(1/n) = nth root of a27^(1/3) = 3

Worked example: 4^(x + 1) = 8^x. Write both in base 2: 2^(2x + 2) = 2^(3x), so x = 2.

Surds

Simplify by pulling out perfect squares: sqrt(72) = sqrt(36 × 2) = 6 sqrt(2). Only like surds add: 3 sqrt(5) + 2 sqrt(5) = 5 sqrt(5). To rationalise, multiply by the conjugate: 1/(sqrt(3) + sqrt(2)) = (sqrt(3) − sqrt(2))/(3 − 2) = sqrt(3) − sqrt(2).

Test yourself: 10 questions, 60 s each

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