Algebra Quiz: Identities, Surds and Linear Equations Practice
10 timed algebra questions for SSC and railway exams. X + 1/x identities, cubes, linear equations, line graphs, surds and indices, with solutions.

Algebra Quiz: Identities, Surds and Linear Equations Practice
Tip: use keys 1-4 to answer, Enter for next.
Answers to the starter quiz
Spoilers! These are the Starter quiz’s answers. Easy, Medium, Hard and Mixed rounds show their own answers when you finish.
If x + 1/x = 5, what is the value of x² + 1/x²?
- 25
- 23
- 27
- 21
Answer: 23. Square both sides: x² + 2 + 1/x² = 25, so x² + 1/x² = 23.
If a + b = 10 and ab = 21, what is the value of a³ + b³?
- 370
- 390
- 350
- 430
Answer: 370. a³ + b³ = (a + b)³ − 3ab(a + b) = 1000 − 630 = 370. (Check: a, b = 3 and 7: 27 + 343 = 370.)
If x − 1/x = 3, what is the value of x³ − 1/x³?
- 27
- 30
- 36
- 33
Answer: 36. x³ − 1/x³ = k³ + 3k when x − 1/x = k: 27 + 9 = 36.
If a = 5, b = −2 and c = −3, what is the value of a³ + b³ + c³?
- 30
- -90
- 60
- 90
Answer: 90. Since a + b + c = 0, a³ + b³ + c³ = 3abc = 3 × 5 × (−2) × (−3) = 90.
Solve for x: 3(x − 2) − 2(x − 5) = 9.
- 5
- 3
- 7
- 4
Answer: 5. Expand: 3x − 6 − 2x + 10 = 9, so x + 4 = 9 and x = 5.
If 2x + 3y = 12 and 3x − y = 7, what is the value of x + y?
- 4
- 6
- 5
- 7
Answer: 5. From the second equation y = 3x − 7. Then 2x + 9x − 21 = 12, so x = 3 and y = 2: x + y = 5.
What is the area of the triangle formed by the line 3x + 4y = 12 and the two coordinate axes?
- 12 sq units
- 7 sq units
- 8 sq units
- 6 sq units
Answer: 6 sq units. The line meets the axes at (4, 0) and (0, 3). Area = 1/2 × 4 × 3 = 6 square units.
Simplify: sqrt(50) + sqrt(18) − sqrt(8)
- 4 sqrt(2)
- 6 sqrt(2)
- 8 sqrt(2)
- 5 sqrt(2)
Answer: 6 sqrt(2). Pull out squares: 5 sqrt(2) + 3 sqrt(2) − 2 sqrt(2) = 6 sqrt(2). Only like surds can be added.
If 9^x = 27^(x − 1), what is x?
- 2
- 4
- 3
- 6
Answer: 3. Use base 3: 3^(2x) = 3^(3x − 3). Equate powers: 2x = 3x − 3, so x = 3.
1/(sqrt(5) − 2) is equal to
- sqrt(5) + 2
- sqrt(5) − 2
- 2 − sqrt(5)
- (sqrt(5) + 2)/3
Answer: sqrt(5) + 2. Multiply top and bottom by the conjugate sqrt(5) + 2: the denominator becomes 5 − 4 = 1.
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